A ball is thrown upward with an initial velocity V_0 from the surface of the earth. the motion of the ball is affected by a drag force equal to \gammaV^2 ( where m is mass of the ball V is its instaneous velocity and \gamma is a constant) . Time taken by theball to rise to its zenith is : [10 Apr 2019 Shift 1]

Correct Answer is : 1√γgtan−1(√γgv0)

{1}/\sqrt{\\gamma g} \sin ^{-1} (\sqrt{ \frac{\\gamma}{g}} v_{0} )

{1}/\sqrt{\\gamma g} \ln (1+\sqrt{ \frac{\\gamma}{g}} v_{0} )

{1}/\sqrt{\\gamma g} \tan ^{-1} (\sqrt{ \frac{\\gamma}{g}} v_{0} )

{1}/\sqrt{2\\gamma g} \tan ^{-1} (\sqrt{ \frac{2\\gamma}{g}} v_{0} )

JEE Main 10 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 23 of 90

Marks: +1, -0

A ball is thrown upward with an initial velocity V0 from the surface of the earth. the motion of the ball is affected by a drag force equal to γV2 ( where m is mass of the ball V is its instaneous velocity and γ is a constant) . Time taken by theball to rise to its zenith is :

[10 Apr 2019 Shift 1]

1
√γg
sin−1(√
γ
g
v0)
1
√γg
‌ln(1+√
γ
g
v0)
1
√γg
tan−1(√
γ
g
v0)
1
√2γg
tan−1(√
2γ
g
v0)

Validate

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