JEE Main 1-Sep-2021 Shift 2 Solved Paper

Given, mass of CuSO4.5H2O=80g
The concentration of copper sulphate solution is x×10−3‌mol∕L.
Molarity =

Number‌of‌moles‌of‌solute

Volume‌of‌solution(L)

...(i)
Molar mass of CuSO4⋅5H2O = 63.54 + 32 + 16 × 4
= 5 × 18 = 249.54 g/mol
Number of moles of solute =

Weight‌of‌solute

Molecular‌mass‌of‌solute

=

80g

249.54g∕mol

=0.32‌mol
Volume of solution = 5 L
From Eq. (i),
Molarity =

0.3205

5

=64.11×10−3‌mol∕L
∴ x = 64.11
or x ≈ 64
Hence, answer is 64.