The number of atoms in 8 {\g} of sodium is x \times10^{23}. The value of x is ......... . (Nearest integer) [Given : \N_{\A}=6.02 \times10^{23} {\mol}^{-1}Atomic mass of {\Na}=23.0 {\u}] [1 Sep 2021 Shift 2]

JEE Main 1-Sep-2021 Shift 2 Solved Paper

Section: Chemistry

Question : 55 of 90

Marks: +1, -0

The number of atoms in 8g of sodium is x×1023. The value of x is ......... . (Nearest integer) [Given : NA=6.02×1023mol−1Atomic mass of Na=23.0u]

[1 Sep 2021 Shift 2]

Go to Question:

Prev Question

Next Question