JEE Main 09 April 2016 Paper

Section: Mathematics

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Question : 61 of 90

Marks: +1, -0

For x∊R,x≠0,let f0(x)=

1

1−x

and fn+1(x)=f0(fn(x)),n=0,1,2,3... Then the value of f100(3)+f1(

2

3

)+f2(

3

2

) is equal to :

[Main 9 Apr 2016]

8
3
5
3
4
3
1
3

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