Let P = {θ : sin θ - cos θ = \sqrt2 \cos\theta} and Q = {θ : sin θ + cos θ = \sqrt2 sin θ} be two sets. Then [JEE Adv 2011 P1]

Trigonometric Functions & Equations

Section: Mathematics

Question : 21 of 30

Marks: +1, -0

Let P = {θ : sin θ - cos θ = √2cosθ} and Q = {θ : sin θ + cos θ = √2 sin θ} be two sets. Then

[JEE Adv 2011 P1]

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