JEE Advanced 2020 Concept Recapitulation Test 2 Paper 1

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Question : 52 of 54

Marks: +1, -0

If

∫

−√2

√2‌

(2x7+3x6−10x5−7x3−12x2+x+1)

(x2+2)

dx=‌

√2

20

(5π+k2), then the value of ‌

k

5

must be.

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