JEE Advanced 2020 Concept Recapitulation Test 2 Paper 1

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Question : 51 of 54
 
Marks: +1, -0
The solution of the differential equation ‌
d3y
dx3
−8‌
d2y
dx2
=0
satisfying y(0)=‌
1
8
,y1(0)=0
and y2(0)=1 is y=‌
eθx−8x+7
λ
.
The numerical value of ‌
λ
10
is.
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