The set of values of θ satisfying the inequation 2sin^2\theta - 5sin\theta + 2 > 0, where 0 < \theta < 2\pi, is [JEE Adv 2006 P1]

Correct Answer is : (0,π6) ∪ (5π6,2π)

(0,\pi/6) ∪ ({5\pi}/6 , 2\pi)

IIT JEE Advanced 2006 Paper 1

Section: Mathematics

Question : 84 of 120

Marks: +1, -0

The set of values of θ satisfying the inequation 2sin2θ−5sinθ+2>0, where 0<θ<2π, is

[JEE Adv 2006 P1]

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