IIT JEE Advanced 2006 Paper 1

Section: Mathematics

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Question : 83 of 120

Marks: +1, -0

The value of ∫

(x2−1)dx

x3√2x4−2x2+1

dx is

[JEE Adv 2006 P1]

2√2−
2
x2
+
1
x4
+c
2√2+
2
x2
+
1
x4
+c
1
2
√2−
2
x2
+
1
x4
+c
none of these

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