IBPS SO Prelims Exam Model Paper 8

Equation I.
x2 + x – 156 = 0
⇒ x2 + 13x – 12x – 156 = 0
⇒ x(x + 13) – 12(x + 13) = 0
⇒ (x + 13) (x – 12) = 0
⇒ x + 13 = 0 or x – 12 = 0
⇒ x = -13 or x = 12
Equation II.
y2 + y – 182 = 0
⇒ y2 + 14y – 13y – 182 = 0
⇒ y(y + 14) – 13(y + 14) =0
⇒ (y + 14) (y – 13) = 0
⇒ y + 14 = 0 or y – 13 = 0
⇒ y = -14 or y = 13∴ x > y and x < y the relationship between x and y cannot be established.