IBPS SO Prelims Exam Model Paper 8

Calculation:
I. x2 – 15x + 56 = 0
⇒ x2 – 7x – 8x + 56 = 0
⇒ x(x – 7) – 8(x – 7) = 0
⇒ (x – 7) (x – 8) = 0
⇒ x = 7, 8
II. 3y2 – 51y + 216 = 0
⇒ 3(y2 – 17y + 72) = 0
⇒ y2 – 17y + 72 = 0
⇒ y2 – 9y – 8y + 72 = 0
⇒ y(y – 9) – 8(y – 9) = 0
⇒ (y – 9) (y – 8) = 0
⇒ y = 9, 8∴ x ≤ y