IBPS SO Prelims Exam Model Paper 7

Given:
I. x2 - 75x + 350 = 0
II. y2 + 75y + 1250 = 0
Calculation:
I. x2 - 75x + 350 = 0
⇒ x2 - 70x - 5x + 350 = 0
⇒ x(x - 70) - 5(x – 70)= 0
⇒ (x - 70)(x - 5) = 0
⇒ x = 70, 5
II. y2 + 75y + 1250 = 0
⇒ y2 + 50y + 25y + 1250 = 0
⇒ y(y + 50) + 25(y + 50) =0
⇒ (y + 50)(y + 25) = 0
⇒ y = (-50), (-25)
When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is only ONE relation between X and Y i.e. >. So, a relation between x and y is “x > y”.
∴ After comparison, all the values of x and y the relation is “x > y”.