IBPS SO Prelims Exam Model Paper 3

I. 10x2 – x – 24 = 0
⇒ 10x2 – 16x + 15x – 24 = 0
⇒ 2x(5x - 8) + 3(5x - 8) = 0
⇒ (2x + 3)(5x - 8) = 0
⇒ x = −

3

2

= -1.5 or x =

+8

5

= +1.6
II. y2 - 2y = 0
⇒ y(y - 2) = 0
⇒ y = 0 or y = +2
So, when x = -1.5, x < y for y = 0 and x < y for y=+2
And when x = +1.6, x > y for y = 0 and x < y for y=+2
∴ Relation cannot be established