IBPS SO Prelims Exam Model Paper 3

3x2 + x – 30 = 0
⇒ 3x2 – 9x + 10x – 30
⇒ 3x(x - 3) + 10(x - 3) = 0
⇒ (3x + 10)(x - 3) = 0
x = −

10

3

, 3
3y2 + 4y – 4 = 0
⇒ 3y2 + 6y – 2y – 4 = 0
⇒ 3y(y + 2) – 2(y + 2) = 0
⇒ (3y - 2)(y + 2) = 0
y = -2,

2

3

Thus, x = −

10

3

, 3 and y = -2,

2

3

.
Comparing these values of x and y, we get option E