IBPS Clerk Mains 2019 Paper

Quantity A:
Let the distance = x km
According to the given conditions

x

24

−

8

60

=

x

20

−

20

60

x

24

−

x

20

=−

20

60

+

8

60

5x−6x

120

=

−20+8

60

x

120

=

12

60

x = 24 km
Distance = 24 km
Quantity B :
Let the distance = y km and speed = s km/hr
According to the given onditions
y/s – y/ (s+6) = 4/60

y(s+6)−y(s)

s(s+6)

=

1

15

ys+6y−ys

s(s+6)

=

1

15

⇒ 6

y

[s×(s+6)]

=

1

15

⇒ y=

[s×(s+6)]

90

...(1)
and

y

(s−6)

−

y

s

=

6

60

6y

[s×(s−6)]

=

1

10

⇒ y = [s × (s – 6)]/60] ...(2)
From equation 1 and 2
[ s(s + 6)]/ 90 = [s (s – 6)] / 60
⇒ 2s + 12 = 3s – 18
⇒ s = 30 km/hr
From equation 2y = [30 × 24]/ 60 = 12 km
∴ Distance = 12 km
∴ Quantity B < Quantity A