HCU MCA 2013 Paper

Question : 59 of 75

Marks: +1, -0

When 4 dice are thrown, what is the probability that the same number appears on each of them?

1 $/1296$
$1/216$
$1/36$
$24/216$

Solution:

(b) Total Sample space, n(s) = 6 x 6 x 6 x 6 =

6 ^4

Now, favourable cases = {(1,1,1,1), (2,2,2,2)(3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}
Total number of favourable cases, n(E) = 6
∴ Required probability

= { n ( E ) }/ { n ( S ) } = { 6 }/ { 6 ^ { 4 } } = { 1 }/ { 6 ^ { 3 } }

= { 1 } /{ 256 }

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