GATE Civil Engineering (CE) 2019 Shift 2 Solved Paper

Question : 11 of 65

Marks: +1, -0

What is curl of the vector field

2 {x}^{2} {yi}+5 {z}^{2} {j} - 4 yzk

Solution:

Curl

=|\table {i}↖{⋀} , {j}↖{⋀} , k ↖{⋀}; \;{∂}/{∂ x} , \;{∂}/{∂ y} , \;{∂}/{∂ z} ; 2 x^{2} y , 5 z^{2} , -4 y z|

=i↖{⋀}(-4 z-10 z)-j↖{⋀}(0-0)+{k}↖{⋀}(0-2 x^{2})

=-14 zi↖{⋀}-2 x^{2} k↖{⋀}

Go to Question:

Prev Question

Next Question