If {\bo {u}}^{\to}={\bo {a}}^{\to}-{\bo {b}}^{\to}, {\bo {v}}^{\to}={\bo {a}}^{\to}+{\bo {b}}^{\to},|{\bo {a}}^{\to}|=|{\bo {b}}^{\to}|=2 then |{\bo {u}}^{\to} \times {\bo {v}}^{\to}| is equal to

Correct Answer is : 2√16−(→a⋅→b)2

2 \sqrt\overrightarrow{16-({\bo {a} \cdot {\bo {b}}^{\to})^2}

\sqrt\overrightarrow{16-({\bo {a} \cdot {\bo {b}}^{\to})^2}

2 \sqrt\overrightarrow{4-({\bo {a} \cdot {\bo {b}}^{\to})^2}

\sqrt\overrightarrow{4-({\bo {a} \cdot {\bo {b}}^{\to})^2}

EAMCET Engineering 2010 Solved Paper

Section: Mathematics

Question : 4 of 160

Marks: +1, -0

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|=|

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|=2 then |

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| is equal to

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