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Question : 3 of 160
Marks:
+1,
-0
Solution:
‌(+2−)⋅(−)×(−−)‌=(+2−)⋅[×−×−×+×‌−×+×]‌=(+2−)⋅[0−(−)−()+0−(−)+]‌[∵×=×=0]‌=(+2−)⋅(−++)‌{.‌=(+2−)⋅(+)‌=⋅+2⋅−⋅+⋅+2⋅−⋅=0+2(1)−0+(1)+2(0)−(0) {. =2+1=3⋅1=3⋅{⋅(×)} {. =3[]‌‌∵[]=⋅(×)
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