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Question : 104 of 160
Marks:
+1,
-0
Solution:
‌cosec‌15∘+ sec15∘‌=‌| 2(sin‌15∘+cos‌15∘) |
| 2sin‌15∘‌cos‌15∘ |
‌2(sin‌45∘‌cos‌30∘−cos‌45∘‌s‌i‌n‌30∘.‌=‌| +cos‌45∘‌cos‌30∘+sin‌45∘sin‌30∘) |
| sin‌30∘ |
‌=4[‌−‌+‌+‌]‌=4[‌]‌=(√3+1)√2=√6+√2‌
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