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Question : 103 of 160
Marks:
+1,
-0
Solution:
sin‌120∘‌cos‌150∘−cos‌240∘‌s‌i‌n‌330∘
‌=−cos‌30∘‌s‌i‌n‌60∘−cos‌60∘‌s‌i‌n‌30∘
‌=−(sin‌60∘‌cos‌30∘+cos‌60∘‌s‌i‌n‌30∘)
‌=−sin‌(60∘+30∘)=−sin‌90∘
‌=−1
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