Delhi Police Constable Exam Model Paper 7

$6^{\mathit{t}\mathit{h}}$
After crossing, the time taken by each train to reach their destination is in the ratio 16 : 25.
The speed of the second train is 24 kmph.
Formula used:
After crossing each other, if time taken by 2 trains is T1 and T2 respectively then,
S2/S1 = √(T1/T2),
here, S1 and S2 are speeds of first and second train respectively
Calculation:
We have, T1 = 16x, T2 = 25x, S1 = 24 kmph
⇒ $\frac{24}{\mathit{S}}1=\sqrt{\left[16\frac{\mathit{x}}{25}\mathit{x}\right]}$
⇒ $\frac{24}{\mathit{S}}1=\frac{4}{5}$
⇒ $\mathit{S}1=24\times \left(\frac{5}{4}\right)=30$ kmph