Delhi Police Constable 2014 Paper

Question : 48 of 100

Marks: +1, -0

In an election, there were only three candidates namely A, B and C, the winning candidate C got 61.8% votes. If the least voted candidate A got 1910 votes whereas B got twice the votes of A then tell how many votes were polled for candidate C?

9270
6720
9488
8999

Validate

Solution:

A got 1910 votes and B got 3820 votes
Sum of their votes

= 1910 + 3820 = 5730

votes
Let total no. of votes = x
According to the question,
38.2% of x = 5730

x×382/1000=5730

⇒x={5730×1000}/382

=15000

Hence, C got

15000 - 5730 = 9270

votes

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