On dividing the polynomial 8x^3 – 6x^2 + 10x + 3 by (4x + 1), the quotient is 2x^2 + k, where k is equal to :

CTET 2 Math and Science Sep 2016 Paper

Question : 48 of 150

Marks: +1, -0

On dividing the polynomial

8x^3 – 6x^2 + 10x + 3

(4x + 1)

, the quotient is

2x^2 + k

, where k is equal to :

Solution:

2x^{2}-2x+3

________________

4x+1{(8x^{3}-6x^{2}+10x+3)}

\;\;{-(8x^{3}-6x^{2}+10x+3)}/{0}

Now

2x^{2}+k=2x^{2}-2x+3

By the comparing coefficients,

k=-2x+3

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