CTET 2 Math and Science Jul 2013 Paper

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Question : 41 of 120

Marks: +1, -0

If

y=\;\;{x-2}/{x+1},y≠1

, then x equals

$\;\;{y+2}/{1-y}$
$\;\;{y+2}/{y-1}$
$\;\;{y-2}/{y+1}$
$\;\;{2-y}/{1-y}$

Solution:

Given

y=\;\;{x-2}/{x+1}

⇒x-2=y(x+1)

x-2=xy+y

x-xy=y+2

x(1-y)=y+2

∴x=\;\;{y+2}/{1-y}

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