CTET 2 Math and Science Jan 2015 Paper(HM)

Question : 54 of 150

Marks: +1, -0

4 x^{2}+y^{2}+14 x-7 y-4 x y+12

के गुणनखण्डों में एक गुणनखंड है

Solution:

4 x^{2}+y^{2}+14 x-7 y-4 x y+12

\;\; =4 x^{2}+y^{2}+12 x+2 x-6 y-y+9+3-4 x y

\;\; =[(2 x^{2})+(-y)^{2}+(3)^{2}-4 x y-6 y+12 x]+2 x-y+3

\;\; =(2 x-y+3)^{2}+(2 x-y+3)

\;\; =(2 x-y+3)(2 x-y+3+1)

\;\; =(2 x-y+3)(2 x-y+4)

\;\text " अतः दिए गये व्यंजक के गुणनखंडों में एक गुणनखण्ड "\;

(2 x-y+3) \;\text " है। "\;

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