CTET 2 Math and Science Jan 2015 Paper(HM)

Question : 31 of 150

Marks: +1, -0

∆ {\DEF}

और

∆ {\PQR}

में, यदि

{\PQ}= {\DE}, {\EF}= {\PR}

और

{\FD}= {\QR}

है, तब

Solution:

∆\DEF≅ ∆\QPR(\SSS)

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