If 0.001 + 1.01 + 1.001 – (1.03 \times 0.1) + (1.11 \div 0.1) + x = 1.4 \times (1 / 10)^{-1} , then the value of the x is

CTET 2 Math and Science Feb 2016 Paper

Question : 58 of 120

Marks: +1, -0

0.001 + 1.01 + 1.001 –

(1.03 × 0.1) + (1.11 ÷ 0.1) + x

1.4 × (1 / 10)^{-1}

, then the value of the x is

Solution:

0.001+1.01+1.001–(1.03×0.1)+1.1÷0.1+x

=1.4×(\;\;{1}/{10})^{-1}

\;\;{1}/{1000}+\;\;{1010}/{1000}+\;\;{1001}/{1000}-\;\;{103}/{1000}+\;\;{11100}/{1000}+{x}=\;\;{1400}/{1000}×10

⇒\;\;{1+1010+1001-103+11100}/{1000}+{x}=\;\;{14000}/{1000}

⇒x=\;\;{14000}/{1000}-\;\;{13009}/{1000}=\;\;{991}/{1000}=0.991

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