CTET 2 Math and Science Feb 2016 Paper

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Question : 57 of 120

Marks: +1, -0

If

x = 2/ 3

and

y = 3 /4

, then a rational number between

(x – y)^{–l}

and

(x^{–1} – y^{–1})

is

$1/ 6$
$- 71 / 12$
$2/ 3$
$- 71/ 2$

Solution:

x=2/3

y=3/4

Value of

(x-y)^{-1}=(\;\;{2}/{3}-\;\;{3}/{4})^{-1}=-\;\;{1}/{12}=-12

Value of

x^{-1}-y^{-1}=\;\;{1}/{x}-\;\;{1}/{y}=\;\;{3}/{2}-\;\;{4}/{3}=\;\;{1}/{6}

Hence required number is

-71/12

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