If 2 x-3 y=5 and x y=6 then what is the value of (4 x^2+9 y^2) ?

CTET 2 Math and Science 7 Jan 2022 Paper

Question : 39 of 150

Marks: +1, -0

2 x-3 y=5

and

x y=6

then what is the value of

(4 x^2+9 y^2)

Solution:

⇒ 2 x-3 y=5

Both of side square

⇒(2 x-3 y)^2=(5)^2

⇒ 4 x^2+9 y^2-12 x y=25

Put the value

x y=6

⇒ 4 x^2+9 y^2-12 × 6=25

⇒ 4 x^2+9 y^2=25+72=97

∴

The value of

(4 x^2+9 y^2)

is 97

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