CTET 2 Math and Science 7 Jan 2022 Paper

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Question : 38 of 150

Marks: +1, -0

If

\;{2(3 y-4)+6}/{3 y-(4+5 y)}=\;{3}/{5}

then the value of

(9 y+1)

is

$-1$
$\;{1}/{2}$
$\;{3}/{2}$
$-2$

Solution:

According to the question

⇒ 6 y-8+6 \/ 3 y-4-5 y=3 \/ 5

⇒ 6 y-2 \/-2 y-4=3 \/ 5

Doing the cross multiply

⇒ 5(6 {\y}-2)=3(-2 {\y}-4)

⇒ 30 {\y}-10=-6 {\y}-12

⇒ 36 {\y}=-2

⇒ {\y}=-1 \/ 18

Put the value of

y(9 y+1)

equation

⇒ 9 ×(-1 \/ 18)+1=1 \/ 2

∴

The value of

(9 y+1)

is

1 \/ 2

.

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