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Question : 144 of 180
Marks:
+1,
-0
Solution:
‌Let, ‌y‌=sin‌−1[x√1−x−√x√1−x2]
‌=sin‌−1[x√1−(√x)2−√x√1−x2]
‌=sin‌−1x−sin‌−1√x
[Using sin‌−1x−sin‌−1y=sin‌−1[x√1−y2−y√1−x2]
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