CLAT 2020 Question Paper with answer key for online practice

Average number of males in Chhattisgarh, Jharkhand and Andhra Pradesh
$=\left[\frac{\left(15+15+7\right)}{3}\right]\times 1000$
$=\frac{37}{3}$ (thousand)
Average number of females in West Bengal, Jharkhand and Odisha
$=\left[\frac{\left(21+15+14\right)}{3}\right]\times 1000$
$=\frac{50}{3}$ (thousand)
Required less percentage $=\left[\frac{\left[\left(\frac{50}{3}\right)-\left(\frac{37}{3}\right)\right]}{\left(\frac{50}{3}\right)}\right]\times 100$
$=\left[\frac{\left(\frac{13}{3}\right)}{\left(\frac{50}{3}\right)}\right]\times 100$
$=\left(\frac{13}{50}\right)\times 100=26\%$ less