CAT Exam Model Paper 2 with solutions for free online practice

Copper in 4 kg =$\frac{4}{5}$kg
and Zinc in 4 kg = $4\times \frac{4}{5}=\frac{16}{5}$kg
Copper in 5 kg = $5\times =\frac{1}{6}=\frac{5}{6}$kg
Zinc in 5 kg = $5\times =\frac{5}{6}=\frac{25}{6}$kg
Therefore, Copper in mixture = $\frac{4}{5}+\frac{5}{6}=\frac{49}{30}$kg
and Zinc in the mixture = $\frac{16}{5}+\frac{25}{6}=\frac{221}{30}$kg
Therefore, the required ratio = 49 : 221