CAT Exam Model Paper 1 with solutions for free online practice

Question : 72 of 100

Marks: +1, -0

Along a road lie on an odd number of stones placed at intervals of 10 m. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried out the job starting with the stone in the middle, carrying stones in succession, thereby covering a distance of 4.8 km. Then the number of stones is

Validate

Solution:

(d) Totally, a person covers 4.8 km. That means he covers 2.4 km on one side and 2.4 km on other side. So, distances he will be covering will be 20 + 40 + 60 + ...

∴2400 = ( { n }/ { 2 } ) ( 2 ×20 + ( n - 1 ) 20 ) = 10 n ( n + 1 )

After solving, we get n = 15
∴ Total number of stones = 15 + 15 + 1 = 31

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