BPSC 65th Prelims Exam 15 Oct 2019 Solved Paper

Total students $=80$
Students playing carrom
$=\frac{80\times 60}{100}=48$
Students playing chess
$=80\times \frac{45}{100}=36$
Students playing neither chess nor carrom $=\frac{80\times 10}{100}=8$
$\therefore$ Number of students who play both chess and carrom $=\left(48+36+8\right)$ -80
$=92-80=12$
$\therefore$ The number of students who play only chess $=36-12=24$