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Question : 117 of 150
Marks:
+1,
-0
Solution:
=
− ,
=
x++(1−x) and
=
y+x+(1+x−y) [] =
.× =
|| = 1 [1 + x - y - x +
x2] - [
x2 - y]
= 1 - y +
x2−x2 + y]
= 1
Hence
[] is independent of x and y both
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