BITSAT 2018 Paper

Rewrite the given differential equation as follows :

dy

dx

+

2x

x2−1

y =

1

x2−1

, which is a linear form
The integrating factor I.F.
= e∫

2x

x2−1

dx = eln(x2−1) = x2 - 1
we get (x2−1)

dy

dx

+ 2xy = 1
⇒

d

dx

[y(x2−1)] = 1
On integrating we get y(x2−1) = x + c