BITSAT 2005 Solved Question Paper

Given equation of lines are
xy+2x+2y+4=0
(x+2)(y+2)=0
x+2=0,y+2=0 ........(i)
x+y+2=0 ........(ii)
These three lines makes an right triangle CAB right angled at A.
The circumcentre of a triangle is the mid point of BC i.e. (−1,−1).