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Question : 30 of 150
Marks:
+1,
-0
Solution:
Since the given vectors
α++,+β+, and
++λ are coplanar, then
||=0 Applying
C2→C2−C1,C3→C3−C2 ⇒
|| α | 1−α | 0 |
| 1 | β−1 | 1−β |
| 1 | 0 | γ−1 |
|=0 ⇒(1−α)(1−β)(1−γ) ||=0 ⇒(1−α)(1−β)(1−γ) [(1)−1(−−)]=0 But
α≠1,β≠1 and
γ≠1 ∴−1++=0 ⇒++=1
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