BA LLB Banaras Hindu University 2019 Solved Paper

Question : 122 of 170

Marks: +1, -0

Two pipes

A

and

B

can fill a tank in

24 {min}

and 48 min respectively. If both the pipes are opened simultaneously after how much time should

B

be closed so that tank is full in 16 min?

Solution:

Let pipe

B

be closed after

x

minutes.
Then, work done by (Pipe

A

in 16 min + Pipe

B

in x min)=1

⇒ \;\; \;{16}/{24}+\;{x}/{48}=1

(32+x)=48

x=16 {min}

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