AP ICET 2019 Shift 2 Paper

Question : 150 of 200

Marks: +1, -0

A bag contains 4 red and 5 black balls. Another bag contains 3 red and 6 black balls. One ball is drawn from the first bag and two balls are drawn from the second bag at random. The probability that out of the three balls, two are black and one is red is

$5/{18}$
${15}/{54}$
${77}/{228}$
${25}/{54}$

Validate

Solution:

(i) Red ball from bag 1 and two black balls from bag 2.
(ii) black ball from bag 1 and Red ball and black ball from bag 2.
Required Probability

=\;{4}/{9} × \;{6 c_{2}}/{9 c_{2}}+\;{5}/{9} × \;{3 × 6}/{9 c_{2}}

=\;{5}/{27}+\;{5}/{18}=\;{10+15}/{54}=\;{25}/{54}

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