AP ICET 2019 Shift 2 Paper

Question : 102 of 200

Marks: +1, -0

The area of a trapezium is

1/2 (a^2-b^2)

sq. units, where a and b are lengths of the parallel sides. Then, the distance between its parallel sides is

Solution:

Given , area of the trapezium

=\;{1}/{2} ×(a^{2}-b^{2})=\;{1}/{2} ×(a-b)(a+b)

⇒ The distance between the two parallel line is

(a-b)

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