AP ICET 2019 Shift 2 Paper

The amount of the work done by A in 4 days$=\frac{4}{24}=\frac{1}{6}$
The remaining work$=\frac{5}{6}$
Let B alone takes t hours to complete the work $\frac{8}{24}+\frac{8}{\mathit{x}}=\frac{5}{6}\Rightarrow \mathit{x}=16$ days
Alternative:
The amount of the work done by A in 12 days is$\frac{1}{2}$
⇒ the remaining half of the work is completed by B in 8 days
⇒ the total work completed by B = 16 days.