AP ICET 2017 Shift 2 Paper

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Question : 119 of 200

Marks: +1, -0

If

270^{∘}<θ<360^{∘}

and

\cotθ=-√{3}

then

\cosθ=

$√3/2$
$1/√3$
$-√3/2$
$-1/√3$

Solution:

Given : 270° < θ < 360°
⇒ θ lies in the fourth quadrant
cos θ is +ve in the fourth quadrant.

\cotθ=-√3

⇒θ=360°–30°=330°

\cos(360°–30°)=\cos30°=√3/2

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