\tan40^{\circ}=x\Rightarrow {\tan250^{\circ}+\tan150^{\circ}}/{1-\tan250^{\circ}\tan150^{\circ}}=

AP ICET 2017 Shift 2 Paper

Question : 118 of 200

Marks: +1, -0

\tan40^{∘}=x⇒\;\;{\tan250^{∘}+\tan150^{∘}}/{1-\tan250^{∘}\tan150^{∘}}=

Solution:

Given : tan 40° = x

\;\;{\tan250^{∘}+\tan150^{∘}}/{1-\tan250^{∘}⋅\tan150^{∘}}=\tan(250^{∘}+150^{∘})

[\text "Using" \tan(A+B)=\;\;{\tanA+\tanB}/{1-\tanA⋅\tanB}]

=\tan400°=\tan(360°+40°)=\tan40°=x

Go to Question:

Prev Question

Next Question