AP ICET 2017 Shift 1 Paper

© examsiri.com

Question : 116 of 200

Marks: +1, -0

If the intercept between the axes of a line has mid-point at

(1,2)

then the equation of the line is

$x-y+1=0$
$x+y-3=0$
$x+2y-5=0$
$2x+y-4=0$

Solution:

x - intercept

=2×1=2

y - intercept

=2×2=4

∴x/2+y/4=1

⇒2x+y=4⇒2x+y–4=0

© examsiri.com

Go to Question:

Prev Question

Next Question