If E\subseteq\mathbb{R} is the maximum possible set on which f(x)=\sqrt{x+2}+ \frac{1}{\log_{10}(1-x)} is defined for x∊E, then E=

Correct Answer is : [−2,0)∪(0,1)

AP ICET 2017 Shift 1 Paper

Question : 115 of 200

Marks: +1, -0

E⊆ℝ

is the maximum possible set on which

f(x)=√{x+2}+\;\;{1}/{\log_{10}(1-x)}

is defined for

x∊E

, then

E=

Solution:

√x+2

is not a real number and hence not defined for x < –2.

\log_10(1-x)

is not defined for x = 1
Hence, E = [–2, 0) ∪ (0, 1)

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