AP ICET 2016 Paper

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Question : 131 of 200

Marks: +1, -0

When the polynomial

7x^3-3x^2+ax-5

is divided by

x+3

, the remainder is

-13

. Then

a=

$308/3$
$208/3$
${-308}/3$
${-208}/3$

Solution:

We know that when f (x) is divided by x – a the remainder is f (a)

f(x)=7x^3-3x^2+ax-5

f(-3)=7(-3)^3-3(-3)^2-3a-5

-13=-189-27-3a-5

3a=-221+13

3a=-208

a=-208/3

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