AP ICET 2016 Paper

Question : 130 of 200

Marks: +1, -0

The angles of elevation of the top of a building measured from two points A, B on the horizontal ground and on the same side of the building are respectively 30°, 60°. If A, B and the foot of the building are collinear and AB = 400 metres, then the height of thatbuilding, in metres, is

$200√3$
$200$
$100(√3-1)$
$100(√3+1)$

Validate

Solution:

Let PQ be the tower of height ‘h’
A and B are the points of observation
on the horizontal ground.
We have

{h}={d}/{\cotθ_{1}-\cotθ_{2}}={400}/{\cot30°-\cot60°}

={400}/{√{3}-{1}/{√{3}}}=200√{3}

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